Intel 9140N NE80567KE025009 User Manual
Product codes
NE80567KE025009
Intel
®
Itanium
®
Processor 9300 Series Datasheet
21
Electrical Specifications
Figure 2-6. TX Equalization Diagram
Figure 2-7. TX Return Loss
C
-1
C
2
C
0
C
1
V su st
V p re
V p os t
V pre
= A(C
-1
- C
0
- C
1
- C
2
)
V sust = A(C
-1
+ C
0
+ C
1
+ C
2
)
V post = A(C
-1
+ C
0
- C
1
- C
2
)
A
-A
V post - V pre – V sus t = |C
-1
| + |C
0
|+ |C
1
|+ |C
2
| = 1
E xam p le: A=500m V, C
-1
= -0.035, C
0
= 0.685, C
1
= -0.28, C
2
= 0
V pre = 0.500(-0.03 5 – 0.685 + 0.28) = 0.5(-0.44) = -2 20m V
V po st = 0.5 00(-0.0 35 + 0.685 + 0.28) = 0.5(0.93) = 4 65m V
V su st = 0.50 0(-0.03 5 + 0.685 – 0.28) = 0.5(0.3 7) = 185m V
V po st = 0.5 00(-0.0 35 + 0.685 + 0.28) = 0.5(0.93) = 4 65m V
V su st = 0.50 0(-0.03 5 + 0.685 – 0.28) = 0.5(0.3 7) = 185m V
P ea king = 465/1 85 = 2 51%
C
-1
C
0
C
1
C
2
0
% P eaking = V p ost/V sus t
C
0
= 1 – su m o f ab s va lu e o f o the r coe fice nts
TX E Q -B O O S T = 20lo g(V po st/V sus t) = 2 0log (46 5/1 85) = 8dB
C
-1
C
2
C
0
C
1
V su st
V p re
V p os t
V pre
= A(C
-1
- C
0
- C
1
- C
2
)
V sust = A(C
-1
+ C
0
+ C
1
+ C
2
)
V post = A(C
-1
+ C
0
- C
1
- C
2
)
A
-A
V post - V pre – V sus t = |C
-1
| + |C
0
|+ |C
1
|+ |C
2
| = 1
E xam p le: A=500m V, C
-1
= -0.035, C
0
= 0.685, C
1
= -0.28, C
2
= 0
V pre = 0.500(-0.03 5 – 0.685 + 0.28) = 0.5(-0.44) = -2 20m V
V po st = 0.5 00(-0.0 35 + 0.685 + 0.28) = 0.5(0.93) = 4 65m V
V su st = 0.50 0(-0.03 5 + 0.685 – 0.28) = 0.5(0.3 7) = 185m V
V po st = 0.5 00(-0.0 35 + 0.685 + 0.28) = 0.5(0.93) = 4 65m V
V su st = 0.50 0(-0.03 5 + 0.685 – 0.28) = 0.5(0.3 7) = 185m V
P ea king = 465/1 85 = 2 51%
C
-1
C
0
C
1
C
2
0
% P eaking = V p ost/V sus t
C
0
= 1 – su m o f ab s va lu e o f o the r coe fice nts
TX E Q -B O O S T = 20lo g(V po st/V sus t) = 2 0log (46 5/1 85) = 8dB