Micron Technology AU8000 Manual De Usuario

Example: 

 

  Speed:  4 

Km/Hour 

  Swath 

Width: 

 12 

m 

 

Therefore: 

 

Area treated 

= 

S x W 

4 x 12 = 

0.08 

ha/min 

 

 

 

  600 

  600 

 

Table 1 shows the coverage of the sprayer for various swath widths and spraying 
speeds. 

4. Calculate 

the 

required output from the sprayer in litres/minute to give the correct 

application rate for the chemical being used. 
The output rate of chemical is given by the area sprayed (in hectares) per minute 
multiplied by the required application rate in litres per hectare. 

 

 

Example: 

 

  Coverage: 

 0.08 

ha/min 

  Application 

rate: 

2 

litre/ha 

 

 

Output     =   

0.08 x 2  =  0.16 litre/min 

 

 

0.007 0.017 0.033 0.050 0.067 0.083 0.100 0.167 

0.010 0.025 0.050 0.075 0.100 0.125 0.150 0.250 

0.013 0.033 0.067 0.100 0.133 0.167 0.200 0.333 

0.017 0.047 0.083 0.125 0.167 0.208 0.250 0.416 

 

 
5.  Select the correct restrictor tube to give the required flow rate.  Table 2 gives the 

typical flow rate for each restrictor tube both with gravity feed and with the optional 
boost pump operating.  These figures are based on measurements with water. Actual 
flow rates will depend upon the viscosity of the chemical being used.  When the boost 
pump is not used, the flow rate will also be affected by the height of the sprayhead 
relative to the chemical tank.  The rates in Table 2 are measured with the tank half full 
and the sprayhead level with the engine. 

 
 

0.075 0.40 

0.150 0.80 

0.300 1.60 

0.600  

1.200