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  RPN: The Automatic Memory Stack 
This method takes one additional keystroke. Notice that the first intermediate result 
is still the innermost parentheses (7 
× 3). The advantage to working a problem 
left–to–right is that you don't have to use 
[
 to reposition operands for 
nomcommutaiive functions ( 
…
 and 
q
 ). 
However, the first method (starting with the innermost parentheses) is often 
preferred because: 
„
It takes fewer keystrokes. 
„
It requires fewer registers in the stack. 
Note 
When using the left–to–right method, be sure that no more than 
four intermediate numbers (or results) will be needed at one 
time (the stack can hold no more than four numbers). 
The above example, when solved left–to–right, needed all registers in the stack at 
one point: 
Keys: 
Display: 
Description: 
4
‘
 14 
‘
)
Saves 4 and 14 as intermediate 
numbers in the stack. 
7
‘
 3 
_
At this point the stack is full with 
numbers for this calculation. 
z
)
Intermediate result. 
›
)
Intermediate result. 
2
…
)
Intermediate result. 
q
)
Final result. 
More Exercises 
Practice using RPN by working through the following problems: 
Calculate: 
(14 + 12) 
× (18 – 12) ÷ (9 – 7) = 78.0000