Motorola MCF5281 사용자 설명서
27-46
MCF5282 User’s Manual
MOTOROLA
Digital Control Subsystem
Figure 27-32. CCW Priority Situation 10
Figure 27-33. CCW Priority Situation 11
The previous situations cover normal overlap conditions that arise with asynchronous
trigger events on the two queues. An additional conflict to consider is that the freeze
condition can arise while the QADC is actively executing CCWs. The conventional use for
the debug mode is for software/hardware debugging. When the CPU enters background
debug mode, peripheral modules can cease operation. When freeze is detected, the QADC
completes the conversion in progress, unlike the abort that occurs when queue 1 suspends
queue 2. After the freeze condition is removed, the QADC continues queue execution with
the next CCW in sequence.
trigger events on the two queues. An additional conflict to consider is that the freeze
condition can arise while the QADC is actively executing CCWs. The conventional use for
the debug mode is for software/hardware debugging. When the CPU enters background
debug mode, peripheral modules can cease operation. When freeze is detected, the QADC
completes the conversion in progress, unlike the abort that occurs when queue 1 suspends
queue 2. After the freeze condition is removed, the QADC continues queue execution with
the next CCW in sequence.
Trigger events that occur during freeze are not captured. When a trigger event is pending
for queue 2 before freeze begins, that trigger event is remembered when the freeze is
for queue 2 before freeze begins, that trigger event is remembered when the freeze is
T1
T1
PAUSE
Q1:
Q2:
QS:
IDLE
ACTIVE
IDLE
ACTIVE
IDLE
0010
0110
1010
0010
ACTIVE
0000
IDLE
Q1:
PF1
C1
C2
0000
1010
0101
ACTIVE
PAUSE
0110
Q2:
T2
PF2
C1
C2
C3
C4
CF1
C3
C4
CF2
T2
C3
SUSPEND
ACTIVE
C1
ACT
SUSPEND
T2
TOR2
T2
TOR2
RESUME = 0
C2
T1
T1
C3
C4
CF1
PAUSE
Q1:
Q2:
QS:
IDLE
ACTIVE
IDLE
ACT
IDLE
0010
0110
1010
0010
ACTIVE
0000
IDLE
Q1:
PF1
C1
C2
0000
1010
0101
ACTIVE
PAUSE
0110
Q2:
T2
SUSPEND ACT
C1
ACTIVE
SUSPEND
T2
TOR2
T2
TOR2
C2
PF2
C4
CF2
T2
C3
C2
C4
RESUME = 1