Texas Instruments LM3429 Evaluation Boards LM3429BKBSTEVAL/NOPB LM3429BKBSTEVAL/NOPB 데이터 시트

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LM3429BKBSTEVAL/NOPB
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=
=
sec
rad
173
.
1
=
sec
rad
k
37
5630
5 x
5630
5 x
1
Z
Z
2
P
=
Z
)
,
min(
1
Z
1
P
Z
Z
T
5
0
U
x
=
T
0
U
=
5630
=
04
.
0
A
1
467
.
1
:
x
x
V
620
533
.
0
x
(
)
D
1+
R
I
LIM
LED
x
x
V
620
D
x
c
sec
rad
k
37
=
=
=
533
.
0
95
.
1
2
x
:
H
33
467
.
0
P
x
D
r
2
D
c
x
L1
D x
1
Z
Z
=
sec
rad
= 110k
1 + D
Z
P1
 =
1.467
1.95
:
 x 6.8 
P
F
r
D
 x C
O
0.04
:
R
LIM
=
:
04
.
0
=
=
=
6.13A
mV
245
mV
245
I
LIM
R
LIM
:
=
=
=
041
.
0
6A
R
LIM
mV
245
mV
245
I
LIM
F
8
.
6
C
O
P
=
x
A
1
=
I
LED
I
RMS
CO-
=
1- 0.677
677
.
0
1.45A
x
1- D
MAX
D
MAX
=
D
I
LED
x
=
'
i
PP
-
LED
SW
f
x
r
D
x C
O
0
=
=
kHz
00
7
95
.
1
x
x
:
5 mA
467
.
0
A
1 x
F
8
.
6
P
'
i
PP
-
LED
f
'
i
r
SW
PP
-
LED
D
x
x
D
I
LED
x
C
O
=
0
=
F
84
.
6
P
=
kHz
00
7
mA
5
95
.
1
x
x
:
467
.
0
A
1 x
C
O
SNVS616G – APRIL 2009 – REVISED MAY 2013
(105)
The closest standard capacitor is 6.8 µF therefore the actual
Δ
i
LED-PP
is:
(106)
Determine minimum allowable RMS current rating:
(107)
The chosen components from step 5 are:
(108)
6. PEAK CURRENT LIMIT
Solve for R
LIM
:
(109)
The closest standard resistor is 0.04
Ω
therefore I
LIM
is:
(110)
The chosen component from step 6 is:
(111)
7. LOOP COMPENSATION
ω
P1
is approximated:
(112)
ω
Z1
is approximated:
(113)
T
U0
is approximated:
(114)
To ensure stability, calculate
ω
P2
:
(115)
34
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