Omron C200HE ユーザーズマニュアル

In the following example, DBSL(––) is used to divide the signed binary contents
of IR 002 and IR 001 with the signed binary contents of DM 0021 and DM 0020
and output the result to LR 24 through LR 21.

DBSL(––)

001

DM 0020

LR 21

00000

LD

00000

00001

DBSL(––)

001

DM

0020

LR

21

00000

Dd: IR 001

B

1

5

C

Dr: DM 0020

0

0

1

A

R: LR 21

D

F

7

0

R+1: LR 22

F

F

F

A

(–8,736,420)

(26)

(–336,016 and –4)

Dd+1: IR 002

F

F

7

A

Dr+1: DM 0021

0

0

0

0

R+2: LR 23

F

F

F

C

R+3: LR 24

F

F

F

F

Remainder (–4)

Quotient (–336,016)

: First word in range

IR, SR, AR, DM, HR, TC, LR

C: Control data

IR, SR, AR, DM, HR, LR, #

@MAX(––)

C

R

1

D

D: Destination word

IR, SR, AR, DM, HR, LR

MAX(––)

C

R

1

D

N in C must be BCD between 001 to 999.

R

1

 and R

1

+N–1 must be in the same data area.

When the execution condition is OFF, MAX(––) is not executed. When the
execution condition is ON, MAX(––) searches the range of memory from R

1

 to

R

1

+N–1 for the address that contains the maximum value and outputs the maxi-

mum value to the destination word (D).

If bit 14 of C is ON, MAX(––) identifies the address of the word containing the
maximum value in D+1. The address is identified differently for the DM area:

1. For an address in the DM area, the word address is written to D+1. For ex-

ample, if the address containing the maximum value is DM 0114, then #0114
is written in D+1.

2. For an address in another data area, the number of addresses from the be-

ginning of the search is written to D+1. For example, if the address contain-
ing the maximum value is IR 114 and the first word in the search range is
IR 014, then #0100 is written in D+1.